$$ A = \frac{2 \times \rho \times L \times I}{V_{drop_allowed}} $$

$$ I_{rated} \ge I_{load} $$

$$ V_d = \frac{2 \times L \times I \times (R \cos\phi + X \sin\phi)}{1000} $$

For a , the approximate voltage drop ($V_d$) is:

$$ I_{table} \ge \frac{I_{load}}{k_1 \times k_2 \times k_3 \times \dots} $$

A more accurate form for incorporates reactance ($X$):

$$ V_d = \frac{2 \times L \times I \times R_{dc}}{1000} \quad \text{(simplified)} $$



 

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